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优化代码逻辑,优化依赖关联
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parent
dc16d9bc1a
commit
e911920ca7
2
main.py
2
main.py
@ -40,7 +40,7 @@ if __name__ == '__main__':
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message = Request.get_message(i * 100, 100).content.decode('utf-8')
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html = Tools.process_old_html(message)
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if "li" not in html:
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break
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continue
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soup = BeautifulSoup(html, 'html.parser')
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for element in soup.find_all('li', class_='f-single f-s-s'):
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time = None
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BIN
requirements.txt
BIN
requirements.txt
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1
resource/user/o2108817943
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1
resource/user/o2108817943
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@ -0,0 +1 @@
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{'skey': '@0LfHOPDPe', 'uin': 'o2108817943', 'p_skey': 'imlHEb63NeT1kfDnjxanOVSuH48x8dVSrk7YGXZNv1c_', 'p_uin': 'o2108817943', 'pt4_token': 'fQ0VtFhsEtRHeV7H*L4kwhKfPEmpvWw62fk4xMO3yPo_'}
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@ -52,8 +52,19 @@ def get_message(start, count):
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g_tk,
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],
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}
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response = requests.get('https://user.qzone.qq.com/proxy/domain/ic2.qzone.qq.com/cgi-bin/feeds/feeds2_html_pav_all',
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params=params, cookies=cookies, headers=headers)
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try:
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response = requests.get(
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'https://user.qzone.qq.com/proxy/domain/ic2.qzone.qq.com/cgi-bin/feeds/feeds2_html_pav_all',
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params=params,
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cookies=cookies,
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headers=headers,
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timeout=(5, 10) # 设置连接超时为5秒,读取超时为10秒
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)
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except requests.Timeout:
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print("请求超时")
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return None
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return response
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